2v^2+13v-15=0

Solution for 2v^2+13v-15=0 equation:

2v^2+13v-15=0

a = 2; b = 13; c = -15;
Δ = b2-4ac
Δ = 132-4·2·(-15)
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-17}{2*2}=\frac{-30}{4}
=-7+1/2
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+17}{2*2}=\frac{4}{4}
=1
$